I read a post that addressed which column the user clicked but the answer was in C# and I couldn't convert it to VB. So what i need is to determine which column header the user clicked. In my InitializeLayout I have the HeaderClickAction.SortSingle option set.
When the user clicks to resort the grid by a column i want to trap which column they clicked so I can also sort the related report by the same column.
I understand that i would need to use the grid's mouse Click event & trap the column from there. But how would i go about it.
Any code should be in VB as I don't know C# & it would take me an extremely long time to figure out the VB context for the same code.
Thanks
Gary
Hello Gary,
There are different approaches to solve this task. Maybe one possible solution could be:
Private Sub ultraGrid1_MouseClick(sender As Object, e As MouseEventArgs) Dim grid As UltraGrid = DirectCast(sender, UltraGrid) Dim element As UIElement = grid.DisplayLayout.UIElement.LastElementEntered Dim columnHeader As Infragistics.Win.UltraWinGrid.ColumnHeader = TryCast(element.GetContext(GetType(Infragistics.Win.UltraWinGrid.ColumnHeader)), Infragistics.Win.UltraWinGrid.ColumnHeader) If columnHeader IsNot Nothing Then MessageBox.Show("Column click at " + columnHeader.Column.Key) End IfEnd Sub
Let me know if you have any questions.
Regards
Georgi,
Thanks that worked great. But now can I capture which way the sort is going (Ascending or Descending)?