Hi Team,
We are using ultrawebgrid to change column style visible=true but it's showing error
i wanted to visible coumn based on the my conditions
please help me to find the solution
code:
Protected Sub uwgTransfer_InitializeLayout(ByVal sender As Object, ByVal e As Infragistics.WebUI.UltraWebGrid.LayoutEventArgs) Handles
uwgTransfer.InitializeLayout
Try
uwgTransfer.Columns(0).Visible =True
Catch PromisEx As
Exception
Throw
PromisEx
End
Sub
Hi,
I'm glad I could help.
If you have other questions, please feel free to contact me.
Thanks for your reply ,
It's Working fine.
Thanks
As I posted earlier, it is not possible to set the Visible property. You should use the "Hidden" property - your code should look like this:
uwgTransfer.Columns(0).Hidden = ColumCanBeVisible(uwgTransfer.Columns(0).ToString())
Hope this helps.
Thanks For your reply,
While Getting the compilation error in visual studio 2008.
Error Decription :
Property 'Visible' is 'ReadOnly'
Code Part:
uwgTransfer.Columns(0).Visible = ColumCanBeVisible(uwgTransfer.Columns(0).ToString())
Expected REsult :
i wanted to visibile coulmn based on my code conditions.
Can you please share some code
Really appreciate your help..
Hi ranganathanpalanisamy,
What error are you getting? Note that the Visible property is read-only, you can use Hidden to hide or show a column.