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Akshay Shanbhag
45
How to display Tooltip on template data field in web datat grid.
posted


following is my template data field column.
I am using the code for displaying tooltip in web data grid as follows:

  

// For showing the tooltip in the grid.

       

function initGrid(grid, args) {

           

var rows = grid.get_rows();

           

var rowCount = rows.get_length();

           

var cellCount = rowCount > 0 ? rows.get_row(0).get_cellCount() : 0;

           

for (var r = 0; r < rowCount; ++r) {

               

var row = rows.get_row(r);

               

for (var c = 0; c < cellCount; ++c) {

                   

var cell = row.get_cell(c);

                   

var cellEl = row.get_cell(c).get_element();

                    cellEl.title = cell.get_text();

                }

            }

        }


 

But I get link button control's client id on the tooltip in the template data field. However it is working fine for normal columns.

<ig:TemplateDataField Header-Text="<%$ resources:screenlabel="" message_title="">"                                                       

Key="MESSAGE_TITLE" Width="150px">                                                            

<ItemTemplate>                                                              

<als:LinkButton runat="server" ID="lbtnSubject" Text='<%# eval="" message_title="">'                                                

OnClick="lbtnSubject_Click" />                                                             

ItemTemplate>                                              

ig:TemplateDataField>

 

 

I want to display item template text in tooltip.
Thanks

-Akshay

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  • 290
    Suggested Answer
    posted

    Hello Akshay,

    Thank you for contacting Infragistics. I took a look at your question and modified the function initGrid() to match your requirements as follows: 

     

    function initGrid(grid, eventArgs){
            var rows = grid.get_rows();
            var rowCount = rows.get_length();
            var cellCount = rowCount > 0 ? rows.get_row(0).get_cellCount() : 0;
            for (var r = 0; r < rowCount; ++r) {
                var row = rows.get_row(r);
                for (var c = 0; c < cellCount; ++c) {
                    var cell = row.get_cell(c);
                    var cellEl = row.get_cell(c).get_element();
                    var cellText = cell.get_text();
                    cellEl.title = ($(cellText).length == 0) ? cellText : $(cellText).text();
                   
                }
            }
    }

     

    To help reduce the time and complexity, I referenced jquery library. To access jquery, please add the following line in your code in your markup. 

    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" ></script>

     

    Please feel free to reach out to me if this does not answer your question or if anything is unclear.

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