Hi Sanjeev,

You can easily add a new column using a UnboundField.

(In the XamFeatureBrowser is an example how to add UnboundFields).

http://help.infragistics.com/Help/NetAdvantage/WPF/2008.2/CLR3.X/html/xamDataGrid_Add_Unbound_Fields_to_xamDataGrid.html

 

Creating FieldLayouts if

      this.xamDataGrid.FieldLayouts.Add(new FieldLayout());

 

Create the UnboundField:

    UnboundField imageField = new UnboundField();

            imageField.Name = "InternelImage";

            imageField.Label = bitmap;

            imageField.DataType = typeof(BitmapImage);

 

Add the new Field to grid layouts:

  this.xamDataGrid.FieldLayouts[0].Fields.Add(imageField);

 

You can add easily rows just using the:

 

this.xamDataGrid.DataItems.Add(dData);

           

where the dData should have structure as the Fileds in the XamDataGrid.


Best Regards,

Dimi

Infragistics Inc.

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Hi Sanjeev,

The best way to set an image in a row cell is to set the style of the column to support image, and then just set the image as a value of the cell.

record.Cells["InternelImage"].Value = Picture;

In the XamFeatureBrowser is an example how to set image in a Field.

The best way to set an image in a column header is to change the default LabelPresenter style to support image. The default styles are located in …\DefaultStyles\DataPresenter\DataPresenterGeneric_Express.xaml. Changing the default style will allows you to use the default settings without overriding it.  

And you can set the Field Label value to be the image.

this.xamDataGrid.FieldLayouts[0].Fields[0].Label = Picture;

Let me know if that would work in your scenario.

Dimi