Hello Viswanath,

Since in this case we are re-templating the CellValuePresenter and need to create a control template the best method to do this is to create the CellValuePresenterStyle in XAML and then attach it to the field in code behind. For example:

XAML:

<Window.Resources>

   <local:MyConverter x:Key="Conv"/>

   <Style x:Key="style1" TargetType="{x:Type igDP:CellValuePresenter}">

     <Setter Property="Template">

       <Setter.Value>

          <ControlTemplate TargetType="{x:Type igDP:CellValuePresenter}">

             <ListBox ItemsSource="{Binding DataItem.Value,

              Converter={StaticResource Conv},ConverterParameter=Test}" />

                    </ControlTemplate>

       </Setter.Value>

     </Setter>

    </Style>

  </Window.Resources>

C#:

UnboundField ValuesField = new UnboundField();

 Style style = (Style) this.Resources["style1"];

 FieldSettings fs = new FieldSettings();

 fs.CellValuePresenterStyle = style;

 ValuesField.Settings = fs;

Sincerely,

Valerie

Software Developer

Infragistics Inc

Can you also tell me, how to define the third column in the example (the one with lists in each cell) programmatically?

Hi Valerie,

Thank you for the response. The suggested method works. But, I am getting the following alert when I try to use UnboundField.

Unbound field is obsolete: Use Field (or one of its editor specific derived classes) with the new BindingType property set to 'Unbound' or 'UseAlternateBinding' instead. The new 'AlternateBinding' and 'AlternateBindingRetentionMode' properties replace all the UnboundFields 'Binding...' properties.

Hello Viswanath,

You need to set the binding on the unbound field, for example:

UnboundField NameField = new UnboundField();

        NameField.Label = "Name";

        MyConverter conv = new MyConverter();

        Binding binding = new Binding();

        binding.Converter = conv;

        binding.ConverterParameter = "Name";

        NameField.Binding = binding;

Sincerely,

Valerie

Software Developer

Infragistics Inc